(3x-2)=(2x^2-x+1)

Solution for (3x-2)=(2x^2-x+1) equation:

(3x-2)=(2x^2-x+1)

We move all terms to the left:

(3x-2)-((2x^2-x+1))=0

We get rid of parentheses

3x-((2x^2-x+1))-2=0


We calculate terms in parentheses: -((2x^2-x+1)), so:

(2x^2-x+1)

We get rid of parentheses

2x^2-x+1

We add all the numbers together, and all the variables

2x^2-1x+1

Back to the equation:

-(2x^2-1x+1)


We get rid of parentheses

-2x^2+3x+1x-1-2=0

We add all the numbers together, and all the variables

-2x^2+4x-3=0

a = -2; b = 4; c = -3;
Δ = b2-4ac
Δ = 42-4·(-2)·(-3)
Δ = -8
Delta is less than zero, so there is no solution for the equation